Molarity Practice Worksheet Answers Explained Simply

8 min read 11-16-2024
Molarity Practice Worksheet Answers Explained Simply

Table of Contents :

Molarity is a fundamental concept in chemistry that refers to the concentration of a solution, specifically the number of moles of solute per liter of solution. Understanding molarity is essential for anyone working with solutions in laboratory settings or in real-world applications, such as medicine and environmental science. In this article, we will break down molarity, provide a simple explanation of its importance, and guide you through some practice worksheet answers to solidify your understanding. Let's dive into the details! 🧪

What is Molarity?

Molarity (M) is defined as:

[ \text{Molarity (M)} = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} ]

This formula highlights two key components:

  • Number of Moles of Solute: This is the amount of the substance you are dissolving in your solution. A mole is a standard unit used in chemistry to quantify atoms, molecules, or other entities.

  • Volume of Solution: This refers to the total volume of the solution, measured in liters. It's important to ensure that the volume is in liters to accurately calculate molarity.

Importance of Molarity

Molarity is crucial in various fields, including:

  • Laboratory Experiments: Accurate measurements of solute concentrations are vital for performing reactions and experiments.
  • Pharmaceuticals: In the medical field, understanding the concentration of drugs can be critical for dosage and effectiveness.
  • Environmental Science: Molarity helps in understanding pollutant concentrations in water and air.

Common Molarity Calculations

Let’s look at some common scenarios where you might calculate molarity:

Example 1: Calculating Molarity

Suppose you dissolve 5 grams of sodium chloride (NaCl) in enough water to make 0.5 liters of solution. To find the molarity:

  1. Calculate the number of moles of NaCl.

    • The molar mass of NaCl = 58.44 g/mol.
    • Moles of NaCl = (\frac{5 \text{ g}}{58.44 \text{ g/mol}} \approx 0.0857 \text{ moles}).
  2. Use the molarity formula: [ M = \frac{0.0857 \text{ moles}}{0.5 \text{ L}} \approx 0.1714 \text{ M} ]

Example 2: Dilution Calculations

If you have a stock solution with a molarity of 2 M and you want to dilute it to a concentration of 0.5 M, you can use the dilution formula:

[ C_1V_1 = C_2V_2 ]

Where:

  • (C_1) = initial concentration (2 M)
  • (V_1) = volume of stock solution needed
  • (C_2) = final concentration (0.5 M)
  • (V_2) = final volume of diluted solution

To find (V_1) if you want to make 1 liter (1000 mL) of the diluted solution:

[ 2 \text{ M} \times V_1 = 0.5 \text{ M} \times 1000 \text{ mL} ]

Solving for (V_1):

[ V_1 = \frac{0.5 \times 1000}{2} = 250 \text{ mL} ]

You would need to take 250 mL of the 2 M solution and dilute it with water to reach a total volume of 1 liter.

Practice Worksheet Sample Problems

Problem Set

Here are some sample problems you might find in a molarity practice worksheet:

Problem Given Data Solution Steps
1 10 g of KCl in 0.2 L 1. Find moles of KCl. 2. Calculate molarity using M = moles/volume.
2 50 mL of 3 M solution diluted to 200 mL Use dilution formula (C_1V_1 = C_2V_2) to find new molarity.
3 30 g of glucose in 0.5 L 1. Calculate moles of glucose. 2. Molarity = moles/0.5 L.

Problem Solutions Explained

Let’s take a closer look at how to solve these problems.

Problem 1: Molarity Calculation

  1. Calculate Moles of KCl:

    • Molar mass of KCl = 74.55 g/mol.
    • Moles = (\frac{10 \text{ g}}{74.55 \text{ g/mol}} \approx 0.134 \text{ moles}).
  2. Calculate Molarity:

    • M = (\frac{0.134}{0.2} = 0.67 \text{ M}).

Problem 2: Dilution Calculation

Using the earlier formula (C_1V_1 = C_2V_2):

  • (C_1 = 3) M, (V_1 = 50) mL, (V_2 = 200) mL
  • Rearranging: (C_2 = \frac{3 \times 50}{200} = 0.75 \text{ M}).

Problem 3: Molarity of Glucose

  1. Calculate Moles of Glucose:

    • Molar mass of glucose (C6H12O6) = 180.18 g/mol.
    • Moles = (\frac{30 \text{ g}}{180.18 \text{ g/mol}} \approx 0.1666 \text{ moles}).
  2. Calculate Molarity:

    • M = (\frac{0.1666}{0.5} = 0.3332 \text{ M}).

Tips for Mastering Molarity

  1. Practice Regularly: The more problems you work through, the more comfortable you will become with molarity calculations.
  2. Memorize Molar Masses: Having common molar masses memorized can save you time.
  3. Double-Check Units: Always ensure your volumes are in liters when calculating molarity to avoid errors.

By mastering molarity and practicing with these worksheets, you'll be well-equipped to handle any solution concentration problems you encounter in your studies or career! Remember, chemistry can be challenging, but with practice and understanding, it can also be highly rewarding! 🧬